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Ohm's Law and Resistance Virtual Lab

Build DC circuits with a variable supply and live meters, test a resistor, lamp and diode, combine resistors, measure resistivity, find internal resistance from your own graphs and practise with an exam.

  • Physics
  • Secondary to first-year university
  • About 60 minutes
  • Simulation, guided tasks, exam and notes

1Learn: what you will be able to do

Current, p.d. and resistance explain every circuit from a torch to a power grid. By the end of this laboratory you will build circuits, predict their meter readings, find resistance and internal resistance from your own graphs and answer exam-style questions.

Learning outcomes

  • Use V = IR and explain what Ohm's law says about an ohmic conductor.
  • Combine resistors in series and in parallel and find the current and p.d. for each part.
  • Calculate power with P = IV = I²R = V²/R.
  • Use R = ρL/A and find resistivity from a graph of resistance against length.
  • Interpret the I-V characteristics of a resistor, a filament lamp and a diode.
  • Explain emf and internal resistance, and find both from a graph of terminal p.d. against current.
  • Plot data, draw a line of best fit, find a gradient with its uncertainty, and state the electrical safety rules.

Equipment in this virtual laboratory

  • A variable DC supply (0 to 12 V) with an ammeter and a voltmeter, drawn live on the circuit bench.
  • A switchable component: ohmic resistor, resistance wire (four materials, adjustable length and diameter), filament lamp or silicon diode.
  • Series and parallel networks of three resistors, with a meter on every part.
  • A cell with adjustable emf, internal resistance and load.
  • A data table with CSV download, four graphs and three fitting tools with uncertainties.
Limits of the simulation. The meters are ideal, the resistors and wires stay at constant temperature, and the lamp and diode follow simple models. Lead resistance, tolerance, battery discharge and AC effects are ignored. Real components are messier, so use the scatter option to practise handling uncertainty. The real laboratory and the real mains supply can be dangerous, and nothing here replaces your teacher's safety rules.

Where this topic appears in courses

Ohm's law, resistance and DC circuits are part of the electricity content of secondary and first-year university physics in the UK and Cambridge pathways, WAEC/WASSCE, the IB Diploma and North American high-school and introductory university courses. The depth varies: some courses stop at series and parallel circuits, others add resistivity, internal resistance, potential dividers and uncertainty in a practical. The three level tags in the notes (Foundation, Core, Extension) let you match the material to your course. This page supports, and does not replace, the specification you are following. Check it for the exact requirements and the equations you are given in the exam.

2Prepare: ideas and predictions

Scientists predict before they measure. Commit to an answer for each question, then open it to check your reasoning.

V = IR    P = IV    R = ρL/A    V = ε − Ir

Series circuits share the p.d. and keep one current. Parallel circuits share the current and keep one p.d. Everything in this laboratory follows from those statements plus V = IR.

Prediction 1. You double the p.d. across a resistor at constant temperature. What happens to the current and to V/I?
The current doubles and V/I stays the same. For an ohmic conductor current is proportional to p.d., so the V-I graph is a straight line through the origin with gradient R. Observe task 1 tests this.
Prediction 2. A 100 Ω and a 200 Ω resistor are joined in parallel. Is the combined resistance above 200 Ω, between 100 and 200 Ω, or below 100 Ω?
Below 100 Ω. Adding a parallel path gives the current more routes, so the total resistance is smaller than the smallest branch. Here it is 100 × 200 / 300 = 66.7 Ω.
Prediction 3. As the p.d. across a filament lamp rises, does V/I go up, go down, or stay constant?
It goes up. More current heats the filament, the lattice ions vibrate more and the electrons collide with them more often. Observe task 3 gives you numbers from the lab's lamp model.
Prediction 4. A cell has emf 6 V. The voltmeter across it reads less than 6 V when it supplies a current. Why?
Energy is lost against the cell's internal resistance. The terminal p.d. is V = ε − Ir, so the more current you draw, the lower the reading. The gradient of V against I is −r.
Prediction 5. A wire is stretched evenly to twice its length with no change of volume. Does its resistance double, quadruple or stay the same?
It quadruples. The length doubles and the cross-sectional area halves, and R = ρL/A, so R increases by 2 × 2 = 4.

3Experiment: the circuit bench

Choose a circuit and a component, set the supply and read the meters. Use Record reading for a single point, or Record a sweep to take ten points from one tenth of the supply up to its full value. Each record is added to the data table.

4Observe: guided investigations

Five short investigations, each checked against the measurements in your own table. Complete them in order, using the bench above.

5Analyse: predict, test and fit

Use the calculator to predict a circuit with full working, then test it on the bench. Then fit lines to your own data to find resistance, emf and internal resistance, and resistivity, each with an uncertainty.

6Examine: practical examination

Ten multiple-choice questions at three levels and five calculations with numbers generated for you each time. Marking is instant, and you are told which notes to review. Marks are for learning, not an official grade.

7Notes: the complete theory

Eighteen sections from principles to exam technique, with worked examples and diagrams. Use the search box, or open everything and print.

A. Overview and learning outcomes

Electric current is a flow of charge, and every practical circuit, from a torch to a national grid, depends on three linked quantities: current I, potential difference V (p.d.) and resistance R. This laboratory lets you build circuits on a bench, read ammeters and voltmeters, record data and discover the relationships for yourself. The central relationship is Ohm's law: for an ohmic conductor at constant temperature, the current is proportional to the potential difference across it. Almost everything else in the topic (the series and parallel rules, power, resistivity, internal resistance) follows from that idea together with conservation of charge and conservation of energy.

The notes work in three layers. Material marked Foundation needs basic algebra and the idea of a circuit. Core material matches typical A-level, IB Diploma, AP Physics 1, WASSCE and Cambridge AS and A Level courses. Extension material goes towards IB HL, AP Physics C: Electricity and Magnetism and first-year university work, and uses calculus ideas and a little statistics.

The default bench setting is a 100 Ω resistor on a 6 V supply, which draws 60 mA. Before you change anything, predict what the meters will show, then test your prediction. When these notes quote a number from the simulator for a lamp or a diode, that number belongs to the simulator's model, which is described in section J. Real components differ in detail.

Learning outcomes

Foundation

  • Define current as the rate of flow of charge and potential difference as energy transferred per unit charge, and state their units.
  • Connect an ammeter in series and a voltmeter in parallel, and read them correctly.
  • Use V = IR to find any one of the three quantities from the other two.
  • State that in a series circuit the current is the same everywhere and in a parallel circuit the p.d. is the same across each branch.
  • Describe how a filament lamp and a diode differ from an ohmic resistor.
  • Explain why a fuse protects a circuit and why mains electricity is dangerous.

Core (A-level, IB, AP, WAEC)

  • Add resistances in series and combine them in parallel, and find the p.d. and current for every component.
  • Use P = IV = I2R = V2/R and energy in kilowatt-hours.
  • Use R = ρL/A and explain how resistivity differs from resistance.
  • Interpret I-V characteristics for an ohmic resistor, a filament lamp and a semiconductor diode, and explain the shape of each.
  • Use emf and internal resistance, V = ε − Ir, and find both from a graph.
  • Plan an investigation, record data in a table, plot a graph with a line of best fit and state the uncertainty in a gradient.

Extension (HL, AP C, university)

  • Derive I = nAvq and estimate drift speed.
  • Derive the condition for maximum power transfer, R = r, and the efficiency at that point.
  • Analyse a loaded potential divider and explain loading by meters.
  • Use standard errors and 95% intervals for gradients and intercepts, and compare chord with tangent (differential) resistance for a non-ohmic device.
B. Core principles

Current Foundation

Current is the rate of flow of charge: I = ΔQ/Δt. The unit is the ampere (A), one coulomb per second. By convention the current is drawn from the positive terminal of a source round the circuit to the negative terminal. This is conventional current. In a metal the charge carriers are electrons, which drift the opposite way. The simulator's moving dots show conventional current.

Potential difference and emf Foundation

The potential difference between two points is the energy transferred per unit charge as charge moves between them: V = W/Q. The unit is the volt (V), one joule per coulomb. A cell's emf ε is the energy the cell supplies per unit charge passing through it, including the energy wasted inside the cell. The p.d. across the terminals is smaller than the emf whenever current flows, because some energy is lost against the cell's internal resistance. Section C and the simulator's cell mode show this.

Resistance Foundation

Resistance is the ratio of p.d. to current: R = V/I. The unit is the ohm (Ω), one volt per ampere. This is a definition and it works for any component at any point on its characteristic. A large resistance means a small current for a given p.d.

Ohm's law Foundation

Ohm's law is a statement about behaviour, not a definition: the current through an ohmic conductor is directly proportional to the p.d. across it, provided the temperature and other physical conditions stay constant. For such a conductor V/I is the same at every point, so the graph of V against I is a straight line through the origin whose gradient is R. Metals at constant temperature are ohmic. Filament lamps, diodes, thermistors and light-dependent resistors are not. They still have a resistance V/I at each point, but it changes.

Kirchhoff's laws Core

The current law says that the total current into a junction equals the total current out, because charge is conserved. The voltage law says that around any closed loop the sum of the emfs equals the sum of the p.d.s, because energy is conserved. These two laws, plus V = IR for each component, solve every circuit in this lab.

QuantitySeriesParallel
CurrentSame through every componentSplits: I = I1 + I2 + ...
P.d.Shared: V = V1 + V2 + ...Same across every branch
Total resistanceR = R1 + R2 + ...1/R = 1/R1 + 1/R2 + ...
Effect of adding a resistorTotal resistance risesTotal resistance falls
Series and parallel arrangements On the left, three resistors R1, R2 and R3 sit one after another on a single wire. On the right, three resistors R1, R2 and R3 sit on three separate branches between a top rail and a bottom rail. R1R2R3 R1R2R3 Series: one pathsame current Parallel: three paths, same p.d.

Power and energy Core

Power is the rate of energy transfer. When charge Q falls through a p.d. V it transfers energy QV, so P = QV/t = IV. Combining with V = IR gives P = I2R = V2/R. Electrical energy is also sold in kilowatt-hours: 1 kWh = 3.6 MJ. The heating in a resistor is the energy that the charge carriers hand to the lattice in collisions.

Resistivity Core

The resistance of a uniform wire depends on its material and its shape. Doubling the length doubles the resistance, and doubling the cross-sectional area halves it, so R = ρL/A. The constant ρ is the resistivity of the material, in ohm metres (Ω m). Resistance describes an object. Resistivity describes a material. Copper has a resistivity of about 1.7 × 10-8 Ω m, constantan about 4.9 × 10-7 Ω m and nichrome about 1.1 × 10-6 Ω m, which is why nichrome and constantan are used for heating elements and precision resistors while copper is used for cables.

C. Equations and derivations
RelationshipMeaning
I = ΔQ/ΔtCurrent is charge per second
V = W/QP.d. is energy per unit charge
R = V/IDefinition of resistance
P = IV = I2R = V2/RElectrical power
R = ρL/AResistance of a uniform wire
I = nAvqCurrent in terms of the charge carriers
ε = I(R + r), V = ε − IrCell with internal resistance
Vout = Vin R2/(R1 + R2)Unloaded potential divider

Series resistors Core

The same current I flows through each resistor. By the voltage law the supply p.d. is the sum of the p.d.s: V = V1 + V2 + V3. Substituting V = IR for each term gives IR = IR1 + IR2 + IR3. Dividing by I gives R = R1 + R2 + R3.

Parallel resistors Core

Every branch has the same p.d. V. By the current law the total current is I = I1 + I2 + I3. Substituting I = V/R for each term gives V/R = V/R1 + V/R2 + V/R3. Dividing by V gives 1/R = 1/R1 + 1/R2 + 1/R3. For two resistors this is R = R1R2/(R1 + R2), and for n identical resistors it is R/n.

Resistivity from proportionality Core

Imagine a wire cut into n identical pieces joined in series: its resistance is n times that of one piece, so R ∝ L. Imagine n identical wires laid side by side and joined at both ends (in parallel): the resistance is one nth, so R ∝ 1/A. Combining gives R = ρL/A with ρ a constant of the material at a given temperature. For a round wire A = πd2/4, so doubling the diameter divides the resistance by four.

Current and drift speed Extension

Let a conductor of cross-sectional area A contain n charge carriers per unit volume, each of charge q, drifting at mean speed v. In time Δt the carriers in a length vΔt pass a cross-section. That volume is AvΔt, it holds nAvΔt carriers and so a charge nAvqΔt. Dividing by Δt gives I = nAvq. For copper n is about 8.5 × 1028 per cubic metre, so a current of 2 A in a wire of diameter 1 mm gives v = I/(nAq) = 2 / (8.5 × 1028 × 7.85 × 10-7 × 1.60 × 10-19) ≈ 1.9 × 10-4 m/s. The electrons creep along at under a fifth of a millimetre per second. The lamp lights at once because the electric field, which sets all the carriers moving, travels along the wire at a large fraction of the speed of light.

Cell with internal resistance Core

A real cell behaves like an ideal source of emf ε in series with a small resistance r. With an external resistance R the total resistance is R + r, so ε = I(R + r). The p.d. across the terminals is the p.d. across R: V = IR = ε − Ir. The term Ir is sometimes called the lost volts. Compared with y = mx + c, a graph of V (vertical) against I (horizontal) has intercept ε and gradient −r.

A real cell: emf with internal resistance Inside a dashed box is an emf epsilon in series with a small resistor r. The two terminals of the box connect to an external resistor R. A voltmeter V is connected across the terminals and reads the terminal potential difference. Current I flows from the positive terminal through R. εrRVI → cell

Maximum power transfer Extension

The power in the load is P = I2R = ε2R/(R + r)2. Differentiating, dP/dR = ε2[(R + r) − 2R]/(R + r)3, which is zero when R = r. The maximum power is ε2/4r, and at that point the efficiency R/(R + r) is exactly 50%. For example a 9 V cell with r = 3 Ω delivers at most 81/12 = 6.75 W, to a 3 Ω load. The simulator's power graph shows this peak.

Potential divider Core

Two resistors R1 and R2 in series across Vin carry the same current I = Vin/(R1 + R2). The p.d. across R2 is IR2, so Vout = VinR2/(R1 + R2). This holds only if nothing draws current from the output. A load in parallel with R2 lowers the output (worked example 7).

D. Worked examples

Every number below was checked by computation. Try each one yourself first, then compare. Several can be reproduced on the bench or in the prediction calculator in the Analyse step.

Example 1 (Foundation): Ohm's law

A resistor has 12 V across it and carries 0.40 A. Find its resistance, then the current if the p.d. is changed to 9.0 V (the temperature is unchanged).

  1. R = V/I = 12 / 0.40 = 30 Ω.
  2. The resistor is ohmic, so its resistance stays 30 Ω. I = V/R = 9.0 / 30 = 0.30 A.

Resistance 30 Ω. Current at 9.0 V is 0.30 A, which is three quarters of 0.40 A, matching 9/12.

Example 2 (Core): series circuit

Resistors of 100 Ω, 220 Ω and 330 Ω are in series with a 6.0 V supply of negligible internal resistance. Find the current and the p.d. across each resistor.

  1. R = 100 + 220 + 330 = 650 Ω.
  2. I = V/R = 6.0 / 650 = 9.23 mA.
  3. V1 = 9.231 mA × 100 = 0.923 V, V2 = 9.231 mA × 220 = 2.031 V, V3 = 9.231 mA × 330 = 3.046 V.
  4. Check: 0.923 + 2.031 + 3.046 = 6.000 V.

9.23 mA. The largest resistor takes the largest share of the p.d.

Example 3 (Core): parallel circuit

Resistors of 10 Ω, 20 Ω and 30 Ω are connected in parallel across 12 V. Find the total resistance, the branch currents and the total current.

  1. 1/R = 1/10 + 1/20 + 1/30 = 0.1000 + 0.0500 + 0.0333 = 0.18333 S, so R = 5.45 Ω (exactly 60/11).
  2. Branch currents: 12/10 = 1.2 A, 12/20 = 0.60 A, 12/30 = 0.40 A.
  3. Total: 1.2 + 0.60 + 0.40 = 2.2 A. Check: 12 / 5.4545 = 2.2 A.

5.45 Ω (smaller than the smallest branch, 10 Ω) and 2.2 A in total.

Example 4 (Core): internal resistance from one reading

A cell of emf 1.50 V is connected to a 12 Ω resistor. A voltmeter across the cell reads 1.44 V. Find the internal resistance.

  1. The current is the terminal p.d. divided by the external resistance: I = 1.44 / 12 = 0.12 A.
  2. Lost volts = ε − V = 1.50 − 1.44 = 0.06 V.
  3. r = lost volts / I = 0.06 / 0.12 = 0.50 Ω.
  4. Check: ε/(R + r) = 1.50 / 12.5 = 0.12 A.

0.50 Ω.

Example 5 (Core): resistivity

A nichrome wire (ρ = 1.10 × 10-6 Ω m) is 2.5 m long and 0.40 mm in diameter. Find its resistance.

  1. A = πd2/4 = π (0.40 × 10-3)2 / 4 = 1.257 × 10-7 m2.
  2. R = ρL/A = 1.10 × 10-6 × 2.5 / 1.257 × 10-7 = 21.9 Ω.

21.9 Ω. The common slip is to use the diameter in millimetres, or to use d in place of the area.

Example 6 (Core): power and a mains appliance

A kettle is rated 2.3 kW at 230 V. Find the current, the resistance of the element, and the energy used in 3.0 minutes. Which standard plug fuse is suitable: 3 A, 5 A or 13 A?

  1. I = P/V = 2300 / 230 = 10 A.
  2. R = V2/P = 2302 / 2300 = 23 Ω (check: 230 / 10).
  3. Energy = Pt = 2.3 kW × (3/60) h = 0.115 kWh, which is 0.414 MJ.
  4. The fuse must exceed the normal current of 10 A, so 13 A is the suitable choice.

10 A, 23 Ω, 0.115 kWh, 13 A fuse.

Example 7 (Extension): a loaded potential divider

Two 1.0 kΩ resistors form a divider across a 12 V supply. Find the output p.d. across the lower resistor (a) with nothing connected and (b) with a 1.0 kΩ load connected across it.

  1. (a) Vout = 12 × 1000 / 2000 = 6.0 V.
  2. (b) The lower resistor and the load are in parallel: 1000 × 1000 / 2000 = 500 Ω.
  3. Now Vout = 12 × 500 / (1000 + 500) = 4.0 V.

6.0 V unloaded and 4.0 V loaded. A load that is not much larger than the divider resistors pulls the output down. This is the same effect as a cell's terminal p.d. falling when it supplies current.

Example 8 (Extension): emf and internal resistance from a graph

Five readings of terminal p.d. V and current I for a cell are (0.10 A, 1.46 V), (0.20 A, 1.41 V), (0.30 A, 1.37 V), (0.40 A, 1.31 V) and (0.50 A, 1.27 V). Fit V = ε − rI.

  1. Least-squares fit of V against I: gradient −0.480 V/A, intercept 1.508 V.
  2. The standard error of the gradient is 0.016 Ω and of the intercept 0.005 V (three degrees of freedom, so the 95% half-width uses t = 3.18: ±0.052 Ω and ±0.017 V).
  3. So ε = (1.508 ± 0.005) V and r = (0.480 ± 0.016) Ω at one standard error. The line has r2 = 0.9965.
  4. The estimated short-circuit current is ε/r = 1.508 / 0.480 = 3.1 A.

ε = 1.51 V, r = 0.48 Ω. You can reproduce this with the analysis tool by recording a cell sweep.

E. Graphs

Choosing the axes Core

Examination papers and textbooks draw characteristics in two ways. An I-V graph has current on the vertical axis and p.d. on the horizontal axis. The gradient is then 1/R (the conductance) for an ohmic component. A V-I graph, the one used in this lab's tool, has p.d. on the vertical axis and the gradient is R. Always read the axis labels before you interpret a gradient. A rising line on an I-V graph that bends upward means the resistance is falling. A line that bends upward on a V-I graph means the resistance is rising.

The three characteristics Core

V against I for a resistor, a lamp and a diode Three small graphs with V vertical and I horizontal. Left: a straight line through the origin. Middle: a curve that starts shallow and steepens. Right: a curve that rises sharply at small current and then runs almost flat. Ohmic resistorFilament lampDiode VVVIII
  • Ohmic resistor: a straight line through the origin. The gradient of the V-I graph is the constant resistance.
  • Filament lamp: the line curves so that V/I rises with current. A larger current heats the filament, the lattice ions vibrate more and collide more often with the electrons, and the resistance rises. In the lab's lamp model the resistance is 4.2 Ω at 1 V and 12 Ω at 6 V.
  • Semiconductor diode: almost no current until the forward p.d. reaches about 0.6 to 0.7 V for silicon, then the current rises very steeply, with a protective resistor needed to limit it. In reverse bias only a tiny leakage current flows. The V-I graph through the origin shows a long near-vertical rise and then an almost flat stretch: on a V-I graph the diode's p.d. barely changes while the current grows. In the lab, a 3 V supply drives 22.6 mA through a diode with its 100 Ω protective resistor and the p.d. across the diode alone is 0.74 V.

Chord and tangent resistance Extension

For a non-ohmic component the word 'resistance' needs care. The chord or static resistance at a point is V/I at that point, the slope of the line from the origin. The tangent or differential resistance is dV/dI, the slope of the curve at that point. For an ohmic resistor they are equal. For a lamp the tangent value exceeds the chord value. For a diode in forward conduction the tangent resistance is far smaller than the chord value. The analysis tool reports both for a lamp or diode.

Cell graph Core

Plot terminal p.d. V against current I for a cell supplying different loads. Because V = ε − rI the points lie on a straight line with a negative gradient. The intercept on the V axis is the emf (the p.d. when no current flows). The intercept on the I axis would be the short-circuit current ε/r, but you should never actually short-circuit a real cell to find it (section J).

Resistance against length Core

For a wire of fixed material and diameter, R plotted against L is a straight line through the origin with gradient ρ/A. Measure the diameter with a micrometer, work out A, and then ρ = gradient × A. A positive intercept on the R axis suggests contact or lead resistance that does not scale with length.

Power against load Extension

Plotting the load power against R for a cell gives a curve that rises, peaks at R = r and falls slowly. The curve is asymmetric: very large loads draw little current, while very small loads waste most of the power inside the cell.

F. Real-world limits

Temperature Core

Ohm's law holds only when the temperature is steady. In a metal a rise in temperature increases the vibration of the lattice ions, so the conduction electrons collide more often and the resistivity increases. A tungsten lamp filament is hundreds of degrees hot when lit, and its resistance is many times its cold value. This is why a lamp draws a large surge of current in the first moments after it is switched on. In a semiconductor such as the material of a thermistor, heating releases more charge carriers, which usually outweighs the extra collisions, so the resistance of an NTC thermistor falls as it warms. In a few materials at very low temperatures the resistance drops to zero. These are superconductors.

Heating of the test component Core

Even a resistor warms when current flows, because P = I2R. A fine wire can warm enough during an experiment to change its resistance. For that reason, when you test a wire for ohmic behaviour you use small currents, take readings quickly and switch off between them. The simulator keeps resistor and wire resistance constant, which is why they appear ideally ohmic. In a real laboratory a plot for a heavily loaded wire curves upward.

Meters are not ideal Core

An ideal ammeter has zero resistance and an ideal voltmeter has infinite resistance. Real instruments fall short. A moving-coil ammeter or a milliamp range can add an ohm or more in series, and a voltmeter draws a small current. In low-resistance circuits the ammeter matters. In high-resistance circuits the voltmeter matters, because it forms a parallel path and lowers the apparent resistance. Digital multimeters usually have a voltmeter resistance of several megohms. The lab's meters are treated as ideal.

Leads, contacts and tolerance Core

Connecting wires and crocodile clips add small resistances, which matter when the circuit resistance is only a few ohms (for example when measuring the internal resistance of a cell). Resistors are sold with a tolerance: a 470 Ω resistor marked ±5% may be anywhere from 446.5 Ω to 493.5 Ω. A measured gradient that differs from the printed value by less than the tolerance is not a discrepancy.

Real sources Core

The model of an emf in series with a constant r is only approximate. The internal resistance of a real cell rises as it discharges and falls if the cell is warm. A cold lead-acid battery in a car delivers a smaller current than a warm one. Cells of the same type from different batches may have different internal resistances. A supply labelled 5 V from a bench power supply may be regulated so that its terminal p.d. holds steady until a current limit, then collapses.

Direct current only Extension

Everything in this lab is direct current (DC). Alternating current brings in capacitance and inductance as well, and a quantity called impedance replaces resistance. The mains 230 V figure used in some examples is the root-mean-square value, which gives the same heating effect in a resistor as a steady DC p.d. of that size.

G. Planning and carrying out the investigation

Variables Foundation

Every investigation has an independent variable that you change, a dependent variable that you measure, and control variables you hold constant. In an Ohm's law experiment the independent variable is the p.d. (set by the supply), the dependent variable is the current, and the controls include the temperature of the component, its length and its material. If the temperature is not controlled, the result is a hidden second variable.

Investigation 1: is a component ohmic? Core

  1. Connect the component, an ammeter in series and a voltmeter directly across the component. (On the bench, set Single component.)
  2. Start with the supply at its smallest non-zero value and increase it in equal steps. A sweep of ten points from one tenth of the maximum to the maximum is a good plan. Use at least six values.
  3. For each setting record I and V. Switch off or reduce the supply between readings if the component warms.
  4. Reverse the supply and repeat if the component might behave differently in the two directions (a diode does).
  5. Plot V against I. A straight line through the origin shows ohmic behaviour. Use the gradient for R.

Investigation 2: resistivity of a wire Core

Measure the diameter of the wire at several places with a micrometer, taking readings in two perpendicular directions, and take the mean. Fix one end of the wire and move a contact along it to vary the length L. For each length record V and I at a small, constant current and find R = V/I. Plot R against L. The gradient is ρ/A, so ρ = gradient × A with A = πd2/4. In the lab, choose Resistance wire, keep the material and diameter fixed, and record at several lengths.

Investigation 3: emf and internal resistance Core

Connect a cell to a variable resistor (rheostat) and an ammeter in series, with a voltmeter across the cell. Start with the largest resistance so the current is small, and increase the current in steps. Record V and I, and keep each reading brief so the cell does not discharge. Plot V against I: the intercept is ε and minus the gradient is r. Use a fresh cell if a long experiment is planned, and never connect a cell directly across its own terminals.

Investigation 4: series and parallel rules Foundation

Choose three resistors of known values. Measure the total current and supply p.d. for the series arrangement and for the parallel arrangement. Compare V/I with the sum for series and with the reciprocal rule for parallel. Resistor tolerance (5% is common) limits how closely they should agree.

Range, repeats and risk Core

Choose a range that gives a good spread of points while keeping currents below the component's rating. Repeat the whole set if you can, to check for scatter. List the risks (hot wires, battery short circuit, mains) and say how you will control them. A good plan names the apparatus with their ranges and resolutions, explains how each reading will be taken and says how the data will be analysed.

H. Data analysis and uncertainty

Recording data Foundation

Record readings in a table with each column headed by the quantity and its unit, such as I / mA. Give every reading in a column to the same number of decimal places, matching the resolution of the instrument. The simulator's CSV download follows this pattern. Quote final answers to a sensible number of significant figures, usually two or three, no more than the data justify.

Absolute and percentage uncertainty Core

Every measurement has an uncertainty. For a single reading it is often taken as half the smallest division or the last digit on a digital display. The absolute uncertainty has the units of the quantity, for example 0.05 V. The percentage uncertainty is the absolute uncertainty divided by the value, times 100. When quantities are multiplied or divided, add the percentage uncertainties. For R = V/I, the percentage uncertainty in R is the percentage in V plus the percentage in I.

Example: uncertainty in R

A voltmeter reads (5.00 ± 0.05) V and an ammeter reads (0.250 ± 0.005) A. Find R with its uncertainty.

  1. R = 5.00 / 0.250 = 20.0 Ω.
  2. Percentage uncertainty in V is 0.05/5.00 = 1%. In I it is 0.005/0.250 = 2%.
  3. In R it is 1% + 2% = 3%, so the absolute uncertainty is 3% of 20.0 = 0.6 Ω.

R = (20.0 ± 0.6) Ω.

For a quantity raised to a power, multiply the percentage uncertainty by the power. A diameter measured to 2% gives an area, and therefore a resistance, uncertain by about 4%, since R ∝ 1/d2. This is why the diameter is the most important measurement in a resistivity experiment.

Lines of best fit Core

A graph averages out random error. Draw the line of best fit so that points are scattered evenly above and below it. Then find the gradient by choosing two points on the line (not data points) far apart, and quoting the gradient from Δy/Δx with units. To estimate its uncertainty by hand, draw the steepest and shallowest lines that still pass through all the error bars or the scatter of the points. The uncertainty in the gradient is half the difference between their gradients. The intercept is treated the same way.

Least squares and standard errors Extension

Software fits a line y = a + bx by minimising the sum of the squared vertical distances (the residuals). For n points the standard error in the gradient is s/√Sxx, where s2 is the sum of squared residuals divided by n − 2, and Sxx = Σ(x − mean x)2. A 95% interval is the standard error times the Student t value for n − 2 degrees of freedom. With only five points t is 3.18, which is why a small data set has a wide interval. If the fit is forced through the origin there are n − 1 degrees of freedom. The tool in the Analyse step reports the gradient with its standard error and its 95% half-width, and draws two dashed lines for the gradient plus and minus one standard error.

As a check, take the data in worked example 8 of section D. The gradient is −0.480 with a standard error of 0.016, so 0.480 ± 0.016 is about 3.4% in r. Five points scattered by about 0.01 V give a gradient good to a few per cent. More readings over a wider current range would improve this.

Is the intercept consistent with zero? Extension

For a resistor, V = IR predicts zero intercept. A fitted intercept of (0.015 ± 0.038) V is consistent with zero because it is smaller than its own standard error. An intercept clearly different from zero signals a systematic problem such as a zero error on a meter, extra series resistance, or an offset in the supply. The same applies to the R-against-L graph.

Comparing with an accepted value Core

Calculate the percentage difference between your result and the accepted or set value. If the difference is smaller than your estimated uncertainty, the results agree within uncertainty. If it is larger, look for a systematic error rather than blaming random scatter. Averaging many readings reduces random error but cannot remove a systematic one.

I. Apparatus and measurement methods

Connecting meters Foundation

An ammeter goes in series, so that the same current flows through it as through the component. A voltmeter goes in parallel, directly across the component whose p.d. you want. Reversing a digital meter gives a negative reading. An analogue meter may be damaged. When you use a multimeter, set the range above the largest reading you expect and move down, so that a reading is never off scale.

Resolution and range Core

The resolution is the smallest change the meter can show. A digital meter reading 0.250 A has a resolution of 0.001 A. A scale with 0.1 V divisions has a reading uncertainty of about 0.05 V. Choosing a range that makes the reading fill most of the scale reduces the percentage uncertainty. A 0.05 V uncertainty on a 5 V reading is 1%, but on a 0.5 V reading it is 10%.

Variable supply: rheostat or divider Core

To vary the current through a component there are two ways. A rheostat in series changes the total resistance, so the current can only fall from the maximum, and the minimum is not zero. A potential divider uses a variable resistor across the supply with the component connected across part of it, so the p.d. across the component can be set from zero up to the full supply. The divider is preferred for characteristic curves of lamps and diodes. The simulator offers an ideal variable supply that behaves like a divider.

Resistor colour code Foundation

Carbon and metal film resistors use coloured bands: black 0, brown 1, red 2, orange 3, yellow 4, green 5, blue 6, violet 7, grey 8, white 9. The first two bands (or three on a precision resistor) give the digits, the next is the multiplier (a power of ten), and the last gives the tolerance (gold ±5%, silver ±10%). Brown, black, red, gold means 10 × 102 = 1000 Ω, or 1.0 kΩ, at ±5%. Check the manufacturer's key because variants exist.

Measuring wire diameter Core

Use a micrometer screw gauge, which reads to 0.01 mm. Check for a zero error by closing the jaws and subtracting the zero reading. Measure in several places along the wire and at right angles to each other, since the wire may not be perfectly round or uniform. The mean diameter gives A = πd2/4.

Four-terminal measurement Extension

Low resistances (a fraction of an ohm) are hard to measure with two leads because the lead and contact resistances add to the result. In a four-terminal (Kelvin) method one pair of leads carries the current and a separate pair senses the p.d. across the sample. The sensing leads carry almost no current, so their resistance has almost no effect. Data loggers and modern multimeters use this idea to measure very small resistances.

J. Safety and limits of the simulation

What this simulation models Foundation

  • An ideal variable DC supply from 0 to 12 V with ideal meters (an ammeter with zero resistance and a voltmeter with infinite resistance).
  • Ohmic resistors and wires with fixed resistance at constant temperature. Wire resistance is R = ρL/A with the resistivities shown on the controls.
  • A filament lamp described by the empirical model V = R0I(1 + (I/I0)2) with R0 = 2 Ω, chosen so that it draws 0.5 A at 6 V (12 Ω when lit). This reproduces the rise of resistance with current but is not a heat-transfer model.
  • A silicon diode following the Shockley equation with saturation current 10-12 A and ideality factor 1.2, in series with a 100 Ω protective resistor, and no breakdown in reverse.
  • Series and parallel networks and a cell with a constant internal resistance, solved exactly with Ohm's law and Kirchhoff's laws. An optional random scatter of about 0.5% mimics reading error.
What it does not model. Meter resistance, lead and contact resistance, resistor tolerance, self-heating of resistors and wires, battery discharge, real power-supply current limits, noise from the environment and AC effects are all left out. Real experiments will show larger and messier uncertainties.

Real-world safety Foundation

The simulator is harmless. Real circuits are not, and the habits you practise here should carry over safely.

  • Never experiment with mains electricity. A mains supply (230 V in many countries, 120 V in others) can deliver a current through the body that stops the heart. Only use low-voltage supplies (typically 12 V or less) in school and college experiments, from isolated laboratory sources.
  • A cell or battery has a low internal resistance and can supply a very large current if its terminals are joined by a wire. A short circuit can overheat the wire, burn skin, and cause a battery to vent or ignite. Lithium batteries and lead-acid car batteries are especially hazardous. Do not short-circuit them and do not charge disposable cells.
  • A resistor, lamp or wire carrying a large current becomes hot enough to burn. Check ratings. Let components cool before handling.
  • A fuse is a deliberately weak link that melts when the current exceeds its rating, breaking the circuit. In a mains plug it is in the live wire. A residual-current device (RCD) cuts the supply within milliseconds if the current in the live and neutral wires differs, which can happen if current flows through a person to earth. An RCD that trips at about 30 mA is typical in many countries.
  • Do not use damaged leads, do not use wet hands near electrical equipment, and switch off before changing a circuit. Follow your teacher's instructions and the local safety rules of your school or laboratory.

The notes give general information for learning and do not replace training, a risk assessment or the safety rules where you work.

K. Common mistakes
  1. Confusing Ohm's law with the definition of resistance. R = V/I always defines resistance. Ohm's law says that for some conductors it is constant. A lamp has a resistance at every point, but it does not obey Ohm's law.
  2. Wrong meter connection. An ammeter in parallel is almost a short circuit. A voltmeter in series nearly stops the current.
  3. Adding resistors in parallel. Parallel resistors do not add. The combined resistance is smaller than the smallest branch. If your answer is bigger, you have forgotten to take the reciprocal at the end.
  4. Using the gradient of an I-V graph as R. With current on the vertical axis the gradient is 1/R.
  5. Mixing up emf and terminal p.d. Terminal p.d. is lower than emf whenever current flows. They are equal only for an open circuit or zero internal resistance.
  6. Forgetting the internal resistance in series. The current from a cell is ε/(R + r), not ε/R.
  7. Unit errors in resistivity. Using millimetres or the diameter directly instead of the area in square metres. Convert 0.40 mm to 0.40 × 10-3 m and square it.
  8. Treating resistance and resistivity as the same. Resistance depends on shape. Resistivity does not.
  9. Believing current is used up. The current is the same all round a series loop. Energy is transferred, not charge lost.
  10. Power formula slips. Use P = V2/R only with the p.d. across that resistor, and P = I2R with the current through it.
  11. Drawing the line through the origin by habit. Only force the line through the origin if the theory demands it. Otherwise report the intercept.
  12. Rounding too early. Keep extra digits in intermediate steps and round the final answer only.
L. Exam technique

Command words Foundation

Read the verb carefully. State wants a short fact. Define wants a precise statement (for example, potential difference is the energy transferred per unit charge). Calculate wants working and a numerical answer with a unit. Explain wants a reason, usually a chain of linked ideas. Show that gives you the answer, and the marks are for the working, so every step must appear. Suggest expects you to apply knowledge to an unfamiliar situation.

Working and units Core

Write the formula first, substitute with units, then give the result. Examiners can award method marks even when the final answer is wrong. Give the unit every time, with the correct prefix (mA, kΩ). A final answer is typically expected to the number of significant figures of the least precise data, often two or three.

Typical question patterns Core

  • Circuit with several resistors: reduce parallel groups to a single resistance first, add the series parts, then find the total current and work back to find the p.d. and currents in each part.
  • Lamp characteristic: describe the shape, state that resistance rises, and explain in terms of lattice vibrations and electron collisions.
  • Internal resistance: start from ε = V + Ir and match to y = mx + c.
  • Resistivity practical: say what you would plot, what the gradient means, and which measurement dominates the uncertainty (the diameter).
  • Power in a heater: choose the formula that uses the quantities given.

Graph questions Core

Label axes with quantity and unit, choose scales that use more than half of the grid, plot points to the nearest half square and draw one clear best-fit line or smooth curve. Use a large triangle for the gradient and show its coordinates. Say what the gradient and the intercept mean in terms of the physics.

Explanations that gain marks Extension

An explanation of a filament lamp's characteristic that earns full marks usually has three links: the current heats the filament, the lattice ions vibrate with greater amplitude, and the electrons collide more often so the resistance rises. An explanation of the diode should mention the forward threshold, the rapid rise in current once it is exceeded, and the very small reverse current.

Using the lab to prepare Foundation

Work through the guided tasks, then try the practical exam. The review list that follows tells you which note section to revisit. Marks in this lab are for learning, not an official grade.

M. Curriculum map

Courses differ in order, depth and notation. The lists below give topic names only, so that you can see where this laboratory fits. They are not a statement of any specification. Always check your own current specification, syllabus or course outline for the exact content, the equations you are given and the practical skills assessed.

PathwayWhere the topic usually appears
UK and Cambridge (GCSE, IGCSE, AS and A Level)Electricity: current, potential difference and resistance; series and parallel circuits; I-V characteristics; resistivity; electrical power and energy; emf and internal resistance; potential dividers; electrical safety; practical skills in measurement and analysis.
WAEC and WASSCECurrent electricity: Ohm's law; resistors in series and parallel; resistivity; electrical energy and power; emf and internal resistance of cells; measurement of resistance; domestic wiring and safety.
IB DiplomaElectric circuits: charge and current; potential difference; resistance and resistivity; Kirchhoff's laws; internal resistance; potential dividers; power; combinations of resistors; investigations and uncertainty in the internal assessment.
US and North America (high school and introductory university)Electric circuits and DC circuits: Ohm's law; resistivity; series and parallel resistors; power; Kirchhoff's rules; real batteries and internal resistance; household electrical safety; laboratory data analysis.

Use the three level tags to match material to your course. Foundation items suit introductory and lower secondary study. Core items match most upper secondary and first-year university courses. Extension items reach towards higher-level and university work. This laboratory supports your course and does not replace it.

N. Applications

Heating elements Core

Kettles, toasters and electric ovens use a wire of high resistivity, often a nickel-chromium alloy, because it heats strongly and does not oxidise quickly at high temperature. For a 2.3 kW kettle at 230 V the element has a resistance of 23 Ω and carries 10 A. The same current in the supply cable should produce little heating, so cables use thick copper with a tiny resistance.

Cables and energy loss Core

A 20 m run of twin copper cable (40 m of conductor) with a cross-section of 2.5 mm2 has a resistance of 1.68 × 10-8 × 40 / 2.5 × 10-6 = 0.27 Ω. At 13 A the cable dissipates I2R = 45 W as heat and drops 3.5 V. National grids send power at very high voltage so that the current, and the I2R loss, is small for a given power.

Fuses and breakers Foundation

A fuse wire melts when its current rating is exceeded, because the heating I2R becomes too large. A circuit breaker uses a heating strip or an electromagnet to open a switch. Both protect wiring from overheating.

Sensors Core

A thermistor in a potential divider turns temperature into a p.d., and a light-dependent resistor does the same for light. A strain gauge is a thin wire whose resistance changes slightly when it is stretched, since both its length and cross-section change. These sensors all use V = IR and the divider rule.

Batteries and electric vehicles Extension

Internal resistance limits the current a battery can deliver and wastes energy as heat inside it. Engineers choose cells and pack layouts with low internal resistance for high-power uses. Cells in series add emf and internal resistance. Identical cells in parallel keep the emf but divide the internal resistance.

Diodes Core

Diodes allow current in one direction only. They rectify alternating current, protect circuits from reversed supplies and, as light-emitting diodes, give efficient lighting, always with a series resistor to set the current.

O. Extension

Microscopic form of Ohm's law Extension

In the free-electron model, the average drift speed is v = (eE/m)τ, where E is the electric field and τ is the mean time between collisions. Using I = nAve gives a current density J = (ne2τ/m)E = σE, with conductivity σ = 1/ρ. This is the microscopic Ohm's law. Heating raises the collision rate, shortening τ, which explains why the resistivity of a metal rises with temperature.

Temperature coefficient Extension

Over modest ranges the resistance of a metal follows R = R0(1 + αΔT). For copper α is about 0.0039 per kelvin, so heating from 20 °C to 100 °C raises the resistance by a factor of 1 + 0.0039 × 80 = 1.31.

Diode equation Extension

The ideal diode current is I = Is(eV/nVT − 1), with thermal voltage VT about 25.9 mV at room temperature. The current grows exponentially with p.d., so a change of about 60 mV multiplies it by roughly ten when n = 1. That is why the forward p.d. of a silicon diode stays near 0.6 to 0.7 V across a huge range of currents.

Loaded dividers and Thévenin's idea Extension

Any network of resistors and sources, seen from two terminals, behaves like a single emf in series with a single resistance. For the divider in worked example 7 the equivalent source is 6.0 V with 500 Ω, so a 1.0 kΩ load gets 6.0 × 1000/1500 = 4.0 V. This is the same mathematics as a cell with internal resistance.

Statistics of the fit Extension

Weighted fits give less influence to noisier points. Residual plots show whether a straight line is the right model: a systematic curve in the residuals means it is not. Report the number of points, the fit method and the uncertainty.

P. Key points
  • I = ΔQ/Δt, V = W/Q, R = V/I. Resistance is defined for every component at every point.
  • Ohm's law: current is proportional to p.d. for an ohmic conductor at constant temperature. The V-I graph is a straight line through the origin with gradient R.
  • Ammeter in series, voltmeter in parallel.
  • Series: same current, p.d.s add, resistances add. Parallel: same p.d., currents add, 1/R adds. Parallel total is smaller than the smallest branch.
  • P = IV = I2R = V2/R. 1 kWh = 3.6 MJ.
  • R = ρL/A. Resistance depends on the object, resistivity on the material.
  • A filament lamp is non-ohmic because its resistance rises as it heats. A diode conducts one way above a threshold of about 0.6 to 0.7 V.
  • Cell: ε = I(R + r) and V = ε − Ir. Plot V against I: intercept ε, gradient −r.
  • Maximum power transfer occurs when R = r, at 50% efficiency.
  • Quote a gradient with its uncertainty, and compare it with the accepted value within that uncertainty.
  • Never experiment with mains electricity. Never short-circuit a battery.
Q. Glossary
Ampere (A)
The unit of current, one coulomb per second.
Charge carrier
A particle that carries current, such as an electron in a metal.
Chord resistance
V/I at a point on a characteristic.
Conductance
The reciprocal of resistance, in siemens (S).
Conventional current
Current drawn from the positive terminal round the circuit to the negative terminal.
Drift speed
The mean speed of charge carriers along a conductor.
Electromotive force (emf)
Energy supplied per unit charge by a source, in volts.
Internal resistance
The resistance inside a source, which causes lost volts when current flows.
Kirchhoff's laws
Charge is conserved at a junction. Energy is conserved around a loop.
Lost volts
The p.d. Ir across the internal resistance.
Ohm (Ω)
The unit of resistance, one volt per ampere.
Ohmic conductor
A conductor whose current is proportional to p.d. at constant temperature.
Potential difference (p.d.)
Energy transferred per unit charge between two points.
Potential divider
Two or more resistors in series used to obtain a fraction of a p.d.
Resistivity
A property of a material: RA/L, in ohm metres.
Tangent resistance
The slope dV/dI at a point on a characteristic.
Terminal p.d.
The p.d. across a source's terminals while it supplies current.
Tolerance
The permitted percentage difference between a component's marked and actual value.
Volt (V)
The unit of p.d., one joule per coulomb.
R. References

These are general sources for further reading. Titles and publishers are given without links. Look them up through the publisher's home page or your library, and check which edition suits your course.

  • University Physics, by Young and Freedman (Pearson).
  • Physics for Scientists and Engineers, by Serway and Jewett (Cengage).
  • Fundamentals of Physics, by Halliday, Resnick and Walker (Wiley).
  • Physics, by Giancoli (Pearson).
  • An Introduction to Error Analysis, by John R. Taylor (University Science Books).
  • Practical Physics, by Squires (Cambridge University Press).
  • Your own examination board's published specification and practical handbook (check the board's home page for the current version).
  • Your national standards body or the International Bureau of Weights and Measures (BIPM) for the definitions of the SI units.

This page is an independent learning resource. It is not endorsed by any examination board.

8Practise: extra problems

Cells and supplies have negligible internal resistance unless the problem says otherwise. Attempt each problem before opening the answer.

Problem 1 (Foundation)

A 220 Ω resistor is connected across a 9.0 V supply. Find the current and the power it dissipates.

Show the answer

I = V/R = 9.0 / 220 = 0.0409 A = 40.9 mA. P = IV = 0.0409 × 9.0 = 0.368 W (check: V²/R = 81 / 220 = 0.368 W).

Problem 2 (Core)

A 24 Ω and an 8.0 Ω resistor in parallel are connected in series with a 4.0 Ω resistor and a 12 V supply. Find the supply current and the current in each parallel resistor.

Show the answer

Parallel pair: 24 × 8 / 32 = 6.0 Ω. Total 6.0 + 4.0 = 10 Ω, so I = 12 / 10 = 1.2 A. The p.d. across the pair is 1.2 × 6.0 = 7.2 V, so the currents are 7.2 / 24 = 0.30 A and 7.2 / 8.0 = 0.90 A, which add to 1.2 A.

Problem 3 (Core)

What length of nichrome wire (ρ = 1.1 × 10-6 Ω m) of diameter 0.50 mm has a resistance of 10 Ω?

Show the answer

A = π(0.50 × 10-3)2 / 4 = 1.963 × 10-7 m2. L = RA/ρ = 10 × 1.963 × 10-7 / 1.1 × 10-6 = 1.79 m.

Problem 4 (Core)

A car battery of emf 12.6 V and internal resistance 0.040 Ω drives a starter motor that draws 150 A. Find the terminal p.d. and the power wasted inside the battery.

Show the answer

Lost volts = Ir = 150 × 0.040 = 6.0 V, so V = 12.6 − 6.0 = 6.6 V. Power wasted inside = I²r = 150² × 0.040 = 900 W.

Problem 5 (Extension)

A 12 V cell has internal resistance 4.0 Ω. What load gives the greatest power, how large is that power, and what is the efficiency?

Show the answer

The greatest power occurs when R = r = 4.0 Ω. I = 12 / 8.0 = 1.5 A and P = I²R = 2.25 × 4.0 = 9.0 W (check: ε²/4r = 144 / 16 = 9.0 W). The efficiency is R/(R + r) = 50%.

Problem 6 (Extension)

An electric heater is rated 2.0 kW at 230 V. Find the resistance of its element, the current drawn and the energy used in 15 minutes in kilowatt-hours.

Show the answer

R = V²/P = 230² / 2000 = 26.5 Ω. I = P/V = 2000 / 230 = 8.70 A. Energy = 2.0 kW × 0.25 h = 0.50 kWh, which is 1.8 MJ.